Well, guess what?
It works the same way with matrices!
* Remember that inverses undo each other!
So, if our
guy is correct, if we multiply him by A, we should get the identity guy.
By the way, the order won't matter:
* This is the one time that multiplication of matrices is commutative!
OK, so let's check our
:
![]()
![[ row 1: 2 , 3 row 2: -4 , -5 ] times [ row 1: -( 5 / 2 ) , -( 3 / 2 ) row 2: 2 , 1 ] = [ row 1: 1 , 0 row 2: 0 , 1 ] ... the answer is I](/sites/default/files/images/06-matrices-31.gif)
Woo hoo! It worked! Cool!
Believe me, you're going to be stinkin' excited
when you get these right, too!