And the last term:

We took 2x (y^2) out of 6 (x^4) (y^2)
So, we need a 3... and an x^3 ...

2 (x^2) (y^5) - 4x (y^3) + 6 (x^4) (y^2) = 2x (y^2) ( x (y^3) -2y + 3x^3 )

Check it! Does it work? Yep!


YOUR TURN:

Factor 15 (a^2) (b^4) - 5a (b^3) + 20 (a^3) (b^3) + 10 (a^5) (b^7)

Factor

6 (x^4) (y^3) +2 (x^2) (y^2) - 8 (x^5) (y^6)

*Be careful! You'll need to have three terms in your ( ) since we started with three terms.


Remember this -- it will keep popping up:

The First Rule of Factoring:

Always see if you can factor something
out of all the terms. If you can, don't just sit there with your finger up your nose --

DO IT!