123456
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Series and Sigma Notation

Let's try one more:

Find this sum:

the summation of ( 6 - 3k ) as k goes from 0 to 3

the summation of ( 6 - 3k ) as k goes from 0 to 3 ... k = 0 gives ( 6 - 3 ( 0 ) ) , k = 1 gives ( 6 - 3 ( 1 ) ) , k = 2 gives ( 6 - 3 ( 2 ) ) , k = 3 gives ( 6 - 3 ( 3 ) ) ... add them up ... = 6 + 3 + 0 - 3 = 6

TRY IT:

Find the sum:

the summation of ( 5 + 4k ) as k goes from 0 to 2

Find the sum:

the summation of ( k^2 - k ) as k goes from 1 to 5