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Solving Log Equations

Here's another one that's form #1:

Solve Ln( 6x ) = 5

That's the natural log...  Really Log to the base e...

Hit it with the inverse!

e^( Ln( 6 ) ) = e^5 ... the e and the Ln cancel out ... 6x = e^5 ... Leave this guy the way he is. He's not as accurate if you make him a decimal! ... x = e^5 / 6

YOUR TURN:

SolveLog to the base 3( 9x ) = 4

 

SolveLog( x^( 2 ) - 6 ) = 1