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Solving Log Equations

What about this guy?

2 - Log to the base 5( x - 4 ) = 0
There's a number without a log...  form #1.

Get the number alone on one side and everything else on the other:

2 = Log to the base 5( x - 4 )

Zap it!

5^( 2 ) = 5^( Log to the base 5( x - 4 ) ) ... the 5 and the Log to the base 5 cancel ... 25 = x - 4 ... x = 29

 

TRY IT:

Solve Log( x^( 2 ) ) + Log( 9 ) = Log( 6x )

 

Solve Log( 4x + 1 ) = Log( 3x + 7 )